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Example 1, using a separate input items for x, y, z, t and 1 output item for f

{graphviz}
digraph flow {
   rankdir=LR;
   node [shape = circle, len=1.00, color=lightblue2, style=filled]; x y z t f;
   node [shape = rectangle, color=lightblue2, style=filled]; function;
   x -> function;
   y -> function;
   z -> function;
   t -> function;
   function -> f;
}
{graphviz}

        [Test]
        public void AnalyticalFunction()
        {
            AnalyticalFunctionComponent function = new AnalyticalFunctionComponent();
            function.Initialize(null);

            IInputItem x = function.InputItems[0];
            IInputItem y = function.InputItems[1];
            IInputItem z = function.InputItems[2];
            IInputItem t = function.InputItems[3];

            IOutputItem f = function.OutputItems[0];

            Assert.AreEqual(1, x.Values.Count);
            Assert.AreEqual(1, y.Values.Count);
            Assert.AreEqual(1, z.Values.Count);
            Assert.AreEqual(1, t.Values.Count);
            Assert.AreEqual(1, f.Values.Count);

            x.Values[0] = 1.0;
            y.Values[0] = 0.0;
            z.Values[0] = 10.0;
            t.Values[0] = new System.TimeSpan(20, 10, 0, 0);

            function.Update(); // computes f(x,y,z,t) = sin(x + y) + z * t

            log.DebugFormat("Computed analytical function value f({0}, {1}, {2}, {3}) = {4}",
                x.Values[0], y.Values[0], z.Values[0], t.Values[0],
                f.Values[0]);

            Assert.AreEqual(17640000.841470987d, (double)f.Values[0], 0.00001);
        }

Example 2, using an input items containing element set with 1 point for x, y, z and one time for t which is connected as input of the function and computing values in the output item for f

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{graphviz} digraph flow { rankdir=LR; node [shape = circle, len=1.00]; src; node [shape = circle, len=1.00, color=lightblue2, style=filled]; xyzt f; node [shape = rectangle, color=lightblue2, style=filled]; function; src -> xyzt-> function -> f; } {graphviz}
Code Block
java java
[Test] public void AnalyticalFunction2() { AnalyticalFunctionComponent2 function = new AnalyticalFunctionComponent2(); function.Initialize(null); Assert.AreEqual(1, function.InputItems.Count); Assert.AreEqual(1, function.OutputItems.Count); OutputItem source = new OutputItem(); FillItem(source, 0.1, 0.1, 0.5, DateTime.Now); source.AddConsumer(function.InputItems[0]); Assert.AreEqual(default(double), function.OutputItems[0].Values[0]); function.Update(); Assert.AreNotEqual(default(double), function.OutputItems[0].Values[0]); }

Example 3, using input item which has element set with 1 point for x, y, z and one time for t. Then it is connected to the 1st output item of the function. When values in the function are computed - they are passed to that input item.

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Code Block
java java
/// <summary> /// This is the way (conceptually) how it worked in v1. /// </summary> [Test] public void AnalyticalFunction3() { AnalyticalFunctionComponent3 function = new AnalyticalFunctionComponent3(); function.Initialize(null); Assert.AreEqual(0, function.InputItems.Count); Assert.AreEqual(1, function.OutputItems.Count); // create an element set InputItem requiredInput = new InputItem(); FillItem(requiredInput, 0.1, 0.1, 0.5, DateTime.Now); function.OutputItems[0].Consumers.Add(requiredInput); Assert.AreEqual(default(double), function.OutputItems[0].Values[0]); // compute function.Update(); Assert.AreNotEqual(default(double), requiredInput.Values[0], "value in the input item must be changed"); }

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